The equivalent weight of Mohr’s salt, FeSO4 . (NH4)2SO4.6 H2O is equal to

Question

The equivalent weight of Mohr’s salt, FeSO4 . (NH4)2SO4.6 H2O is equal to (A) its molecular weight (B) atomic weight (C) half-its molecular weight (D) one-third its molecular weight.

Tardigrade Admin · Accepted Answer

overset text +2 FeSO4 arrow overset text +3Fe 2(SO4)3 FeSO4 present in Mohr’s salt gets converted into Fe2(SO4)3. This is a one-electron change and hence Eq. wt. of Mohr’s salt is equal to its Mol. wt.

Q. The equivalent weight of Mohr’s salt, $F e S O_{4} . (N H_{4})_{2} S O_{4} .6 H_{2} O$ is equal to

its molecular weight

atomic weight

half-its molecular weight

one-third its molecular weight.

$F e +2 S O_{4} \to F e +3_{2} (S O_{4})_{3}$
$F e S O_{4}$ present in Mohr’s salt gets converted into $F e_{2} (S O_{4})_{3}$ . This is a one-electron change and hence Eq. wt. of Mohr’s salt is equal to its Mol. wt.

Q. The equivalent weight of Mohr’s salt, FeSO4​.(NH4​)2​SO4​.6H2​O is equal to