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  4. The equivalent weight of Mohr’s salt, FeSO4 . (NH4)2SO4.6 H2O is equal to

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Q. The equivalent weight of Mohr’s salt, $FeSO_4 . (NH_4)_2SO_{4}.6 H_2O$ is equal to

Redox Reactions

Solution:

$\overset{\text{ +2}}{ Fe}SO_4 \rightarrow \overset{\text{ +3}}{Fe }_2(SO_4)_3$
$FeSO_4$ present in Mohr’s salt gets converted into $Fe_2(SO_4)_3$. This is a one-electron change and hence Eq. wt. of Mohr’s salt is equal to its Mol. wt.