The equivalent weight of MnO4 is half of its molecular weight when it converts to

Question

The equivalent weight of MnO4 is half of its molecular weight when it converts to (A) Mn2O3 (B) MnO4- (C) MnO2 (D) MnO2-

Tardigrade Admin · Accepted Answer

Equivalent weight =( text molar mass / text change in O N)=(M/2) Thus, change in oxidation number =2 units Change in O.N. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/74bc0de025148fc9b6e7ba2d7310c92a-.png" />

Q. The equivalent weight of $M n O_{4}$ is half of its molecular weight when it converts to

$M n_{2} O_{3}$

$M n O_{4}^{-}$

$M n O_{2}$

$M n O_{2}^{-}$

Equivalent weight $= \frac{molar mass}{change in ON} = \frac{M}{2}$
Thus, change in oxidation number $= 2$ units Change in $O . N$ .

Q. The equivalent weight of MnO4​ is half of its molecular weight when it converts to

Mn2​O3​

MnO4−​

MnO2​

MnO2−​