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  4. The equivalent weight of MnO4 is half of its molecular weight when it converts to

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Q. The equivalent weight of $MnO_4$ is half of its molecular weight when it converts to

Redox Reactions

Solution:

Equivalent weight $=\frac{\text { molar mass }}{\text { change in } O N}=\frac{M}{2}$
Thus, change in oxidation number $=2$ units Change in $O.N$.
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