The equivalent weight of aluminium in Al2O3 will be:

Question

The equivalent weight of aluminium in Al2O3 will be: (A) 13.5 (B) 27 (C) 9 (D) 102

Tardigrade Admin · Accepted Answer

From the molecular formula (Al2O3) , it is clear that valency of metal, Al is 3. Hence, equivalent weight of textAl=( textatomic textweight/ textvalency) =(27/3)=9

Q. The equivalent weight of aluminium in $A l_{2} O_{3}$ will be:

13.5

27

9

102

From the molecular formula $(A l_{2} O_{3})$ , it is clear that valency of metal, Al is 3. Hence, equivalent weight of $Al = \frac{atomic weight}{valency}$ $= \frac{27}{3} = 9$

Q. The equivalent weight of aluminium in Al2​O3​ will be:

13.5

27

9

102

From the molecular formula (Al2​O3​) , it is clear that valency of metal, Al is 3. Hence, equivalent weight of Al=valencyatomicweight​ =327​=9

Q. The equivalent weight of aluminium in $A l_{2} O_{3}$ will be:

From the molecular formula $(A l_{2} O_{3})$ , it is clear that valency of metal, Al is 3. Hence, equivalent weight of $Al = \frac{atomic weight}{valency}$ $= \frac{27}{3} = 9$