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Q. The equivalent weight of aluminium in $ A{{l}_{2}}{{O}_{3}} $ will be:

JIPMERJIPMER 2001

Solution:

From the molecular formula $ (A{{l}_{2}}{{O}_{3}}) $ , it is clear that valency of metal, Al is 3. Hence, equivalent weight of $ \text{Al}=\frac{\text{atomic}\,\text{weight}}{\text{valency}} $ $ =\frac{27}{3}=9 $