Question

The equivalent resistance between $X$ and $Y$ in circuit given, is :

• A. $5\Omega$
• B. $7.5\Omega$
• C. $20\Omega$
• D. $10\Omega$

Answer 1

Answer: (D)

Given circuit is balanced Wheatstone bridge as $\frac{P}{Q}=\frac{R}{S}$
hence between point MN, resistance $10\Omega$ is in effective
Therefore, equivalent circuits is
Equivalent resistance between $XY$ is
$=\frac{(10+10)(10+10)}{(10+10)+(10+10)}$
$=\frac{20\times 20}{40}=10\Omega$