Q.
The equivalent resistance between $X$ and $Y$ in circuit given, is :
Haryana PMTHaryana PMT 2001
Solution:
Given circuit is balanced Wheatstone bridge as $ \frac{P}{Q}=\frac{R}{S} $
hence between point MN, resistance $ 10\,\Omega $ is in effective
Therefore, equivalent circuits is
Equivalent resistance between $XY$ is
$ =\frac{(10+10)(10+10)}{(10+10)+(10+10)} $
$ =\frac{20\times 20}{40}=10\,\Omega $

