Q.
The equivalent resistance between points A and B in the given circuit is
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J & K CETJ & K CET 2011Electromagnetic Induction
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Solution:
The given circuit having parallel and series combination of resistance so we can calculate,
as R1=3+3=6Ω
as R2=3+3=6Ω R31=R11+R21=61+61 ⇒R3=3Ω
and R4=3Ω R1=R31+R41=31+31=32
or R=1.5Ω