The equivalent mass of KMnO 4 in the following reaction is: MnO 4-+5 Fe 2++8 H + arrow Mn 2++5 Fe 2++4 H 2 O ( M = Molecular mass )

Question

The equivalent mass of KMnO 4 in the following reaction is: MnO 4-+5 Fe 2++8 H + arrow Mn 2++5 Fe 2++4 H 2 O ( M = Molecular mass ) (A) ( M /2) (B) ( M /3) (C) ( M /4) (D) (M/5)

Tardigrade Admin · Accepted Answer

Here; equivalent weight of salt = ( textMolecular weight/ textNumber of electron lost or gained) Number of electron lost or gained =5 equivalent mass =( M /5)

Q. The equivalent mass of $K M n O_{4}$ in the following reaction is:

$M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{2 +} + 4 H_{2} O$

$(M =$ Molecular mass $)$

$\frac{M}{2}$

$\frac{M}{3}$

$\frac{M}{4}$

$\frac{M}{5}$

Here; equivalent weight of salt =

$\frac{Molecular weight}{Number of electron lost or gained}$

Number of electron lost or gained $= 5$

equivalent mass $= \frac{M}{5}$

Q. The equivalent mass of KMnO4​ in the following reaction is: MnO4−​+5Fe2++8H+→Mn2++5Fe2++4H2​O (M= Molecular mass )

2M​

3M​

4M​

5M​