Question

The equivalent mass of $KMnO _{4}$ in the following reaction is:

$MnO _{4}^{-}+5 Fe ^{2+}+8 H ^{+} \rightarrow Mn ^{2+}+5 Fe ^{2+}+4 H _{2} O$

$( M =$ Molecular mass $)$

• A. $\frac{ M }{2}$
• B. $\frac{ M }{3}$
• C. $\frac{ M }{4}$
• D. $\frac{M}{5}$

Answer 1

Answer: (D)

Here; equivalent weight of salt =

$\frac{\text{Molecular weight}}{\text{Number of electron lost or gained}}$

Number of electron lost or gained $=5$

equivalent mass $=\frac{ M }{5}$