The equivalent conductance at infinite dilution of a weak acid such as HF

Question

The equivalent conductance at infinite dilution of a weak acid such as HF (A) can be determined by extrapolation of measurements on dilute solutions of HCl, HBr and HI (B) can be determined by measurement on very dilute HF solutions (C) can best be determined from measurements on dilute solutions of NaF, NaCl and HCl (D) is an undefined quantity

Tardigrade Admin · Accepted Answer

According to Kohlrausch 's law, equivalent conductance at infinite dilution of HF, ∧ HF 1 arrow 0=∧ NaF 1 arrow 0+∧ HCl 1 arrow 0-∧ NaCl 1 arrow 0

Q. The equivalent conductance at infinite dilution of a weak acid such as $H F$

can be determined by extrapolation of measurements on dilute solutions of HCl, HBr and HI

can be determined by measurement on very dilute HF solutions

can best be determined from measurements on dilute solutions of NaF, NaCl and HCl

is an undefined quantity

According to Kohlrausch 's law, equivalent conductance at infinite dilution of $H F$ ,
$\land_{H F}^{1 \to 0} = \land_{N a F}^{1 \to 0} + \land_{H Cl}^{1 \to 0} - \land_{N a Cl}^{1 \to 0}$

Q. The equivalent conductance at infinite dilution of a weak acid such as HF