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Chemistry
The equivalent conductance at infinite dilution of a weak acid such as HF
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Q. The equivalent conductance at infinite dilution of a weak acid such as $HF$
VITEEE
VITEEE 2010
A
can be determined by extrapolation of measurements on dilute solutions of HCl, HBr and HI
4%
B
can be determined by measurement on very dilute HF solutions
44%
C
can best be determined from measurements on dilute solutions of NaF, NaCl and HCl
48%
D
is an undefined quantity
4%
Solution:
According to Kohlrausch 's law, equivalent conductance at infinite dilution of $HF$,
$\wedge_{ HF }^{1 \rightarrow 0}=\wedge_{ NaF }^{1 \rightarrow 0}+\wedge_{ HCl }^{1 \rightarrow 0}-\wedge_{ NaCl }^{1 \rightarrow 0}$