Tardigrade
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Tardigrade
Question
Chemistry
The equilibrium constants of a reaction at 298 K and 308 K are 1.0 × 10-2 and 2 × 10-2 respectively, the reaction is
Q. The equilibrium constants of a reaction at
298
K
and
308
K
are
1.0
×
1
0
−
2
and
2
×
1
0
−
2
respectively, the reaction is
3621
189
Equilibrium
Report Error
A
Exothermic
7%
B
Endothermic
80%
C
May be endothermic or exothermic
9%
D
Cannot be predicted
4%
Solution:
Increase in temperature
K
c
value is increased, means
K
f
value is more indicates forward reaction is endothermic