1. Tardigrade
  2. Question
  3. Chemistry
  4. The equilibrium constants of a reaction at 298 K and 308 K are 1.0 × 10-2 and 2 × 10-2 respectively, the reaction is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The equilibrium constants of a reaction at $298\, K$ and $308 \,K $ are $1.0 \times 10^{-2}$ and $2 \times 10^{-2}$ respectively, the reaction is

Equilibrium

Solution:

Increase in temperature $K_{c}$ value is increased, means $K_{f}$ value is more indicates forward reaction is endothermic