The equilibrium constant for the equilibrium PCl5(g) PCl3(g) + Cl2(g) at a particular temperature is 2 × 10-2mol dm-3. The number of moles of PCl5 that must be taken in a one-litre flask at the same temperature to obtain a concentration of 0.20 mol of chlorine at equilibrium is

Question

The equilibrium constant for the equilibrium PCl5(g) <=> PCl3(g) + Cl2(g) at a particular temperature is 2 × 10-2mol dm-3. The number of moles of PCl5 that must be taken in a one-litre flask at the same temperature to obtain a concentration of 0.20 mol of chlorine at equilibrium is (A) 2.0 (B) 2.2 (C) 1.8 (D) 0.2

Tardigrade Admin · Accepted Answer

$2.0$

$2.2$

$1.8$

$0.2$

$0.1$

Q. The equilibrium constant for the equilibrium PCl5​(g)​PCl3​(g)+Cl2​(g) at a particular temperature is 2×10−2mol dm−3. The number of moles of PCl5​ that must be taken in a one-litre flask at the same temperature to obtain a concentration of 0.20 mol of chlorine at equilibrium is

2.0

2.2

1.8

0.2

0.1

$2.0$

$2.2$

$1.8$

$0.2$

$0.1$