Question

The equation of the right bisector plane of the segment joining $(2,3,4)$ and $(6,7,8)$ is

• A. $x+y+z+15=0$
• B. $x+y+z-15=0$
• C. $x-y+z-15=0$
• D. None of these

Answer 1

Answer: (B)

$M\equiv (4,5,6)$
plane passes through 4, 5, 6
$\therefore A(x-4)+B(y-5)+C(z-5)=0$
$A,B,C$ are $4,4,4$
$\therefore \text{ equation is }x-4+y-5+z-6=0$
$\Rightarrow x+y+z=15$