Q. The equation of the right bisector plane of the segment joining $(2,3,4)$ and $(6,7,8)$ is
Vector Algebra
Solution:
$M \equiv(4,5,6)$
plane passes through 4, 5, 6
$\therefore A ( x -4)+ B ( y -5)+ C ( z -5)=0$
$A, B, C $ are $4,4,4$
$\therefore \text { equation is } x -4+ y -5+ z -6=0 $
$\Rightarrow x + y + z =15$