The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is:

Question

The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is: (A)  x-y-z-15=0  (B)  x-y+z-15=0  (C)  x+y+z-15=0  (D)  x+ text y+ text z+15=0

Tardigrade Admin · Accepted Answer

∵ Midpoint of line joining (2, 3,4) and (6, 7,8) is (4, 5, 6) this point is satisfied by one equation x+y+z-15=0 ∴ x+y+z-15=0 is required equation of plane.

Q. The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is:

$x - y - z - 15 = 0$

$x - y + z - 15 = 0$

$x + y + z - 15 = 0$

$x + y + z + 15 = 0$

$x - y - z + 15 = 0$

$∵$ Midpoint of line joining (2, 3,4) and (6, 7,8) is (4, 5, 6) this point is satisfied by one equation
$x + y + z - 15 = 0$
$∴$ $x + y + z - 15 = 0$ is required equation of plane.

Q. The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is:

x−y−z−15=0

x−y+z−15=0

x+y+z−15=0

x+y+z+15=0

x−y−z+15=0