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Q. The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is:

KEAMKEAM 2004

Solution:

$ \because $ Midpoint of line joining (2, 3,4) and (6, 7,8) is (4, 5, 6) this point is satisfied by one equation
$ x+y+z-15=0 $
$ \therefore $ $ x+y+z-15=0 $ is required equation of plane.