The equation of state for 5g of oxygen at a pressure P and temperature T, when occupying a volume V, will be:

Question

The equation of state for 5g of oxygen at a pressure P and temperature T, when occupying a volume V, will be: (A) PV=(.(5/32).)RT (B) PV=5RT (C) PV=(.(5/2).)RT (D) PV=(.(5/16).)RT

Tardigrade Admin · Accepted Answer

No. of moles n=(m/ text molecular weight )=(5/32) So, from ideal gas equation PV=nRT ⇒ PV=(5/32)RT

Q. The equation of state for $5 g$ of oxygen at a pressure $P$ and temperature $T,$ when occupying a volume $V,$ will be:

$P V = (\frac{5}{32}) RT$

$P V = 5 RT$

$P V = (\frac{5}{2}) RT$

$P V = (\frac{5}{16}) RT$

No. of moles $n = \frac{m}{molecular weight} = \frac{5}{32}$
So, from ideal gas equation $P V = n RT$
$\Rightarrow P V = \frac{5}{32} RT$

Q. The equation of state for 5g of oxygen at a pressure P and temperature T, when occupying a volume V, will be:

PV=(325​)RT

PV=5RT

PV=(25​)RT

PV=(165​)RT