Question

The equation of state for $5g$ of oxygen at a pressure $P$ and temperature $T,$ when occupying a volume $V,$ will be:

• A. $PV=\left(\right.\frac{5}{32}\left.\right)RT$
• B. $PV=5RT$
• C. $PV=\left(\right.\frac{5}{2}\left.\right)RT$
• D. $PV=\left(\right.\frac{5}{16}\left.\right)RT$

Answer 1

Answer: (A)

No. of moles $n=\frac{m}{\text{ molecular weight }}=\frac{5}{32}$
So, from ideal gas equation $PV=nRT$
$\Rightarrow PV=\frac{5}{32}RT$