Question

The equation of motion for a body executing SHM is given by $y=1.5\sin (10+5)$. Then the frequency is given by

• A. $5\pi Hz$
• B. $1.5Hz$
• C. $5Hz$
• D. $\pi Hz$

Answer 1

Answer: (C)

$y=1.5\sin (10\pi t+5)$
Comparing with standard equation
$y=a\sin (\omega t+\varphi )$
Frequency, $n=\frac{\omega }{2\pi }$
$=\frac{10\pi }{2\pi }=5Hz$