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Physics
The equation of motion for a body executing SHM is given by y=1.5 sin (10+5). Then the frequency is given by
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Q. The equation of motion for a body executing SHM is given by $y=1.5 \sin (10+5)$. Then the frequency is given by
Uttarkhand PMT
Uttarkhand PMT 2011
A
$5 \, \pi \, Hz$
B
$1.5 \,Hz$
C
$5\, Hz$
D
$ \pi \, Hz$
Solution:
$ y=1.5\sin (10\pi t+5) $
Comparing with standard equation
$ y=a\sin (\omega t+\phi ) $
Frequency, $ n=\frac{\omega }{2\pi }$
$=\frac{10\pi }{2\pi } = 5\,Hz$