The equation of a wave on a string of linear mass density 0.04 kg m-1 is given by y = 0.02(m)sin[2π ((t/0.04(s))-(x/0.50(m)))]. The tension in the string is

Question

The equation of a wave on a string of linear mass density 0.04 kg m-1 is given by y = 0.02(m)sin[2π ((t/0.04(s))-(x/0.50(m)))]. The tension in the string is (A) 4.0 N (B) 12.5 N (C) 0.5 N (D) 6.25 N

Tardigrade Admin · Accepted Answer

T = μ v2 = μ (ω2/k2) = 0.04 ((2π / 0.004)2/(2π / 0.50)2) = 6.25 N

Q. The equation of a wave on a string of linear mass density $0.04 k g m^{- 1}$ is given by
$y = 0.02 (m) s in [2 π (\frac{t}{0.04 ( s )} - \frac{x}{0.50 ( m )})]$ .
The tension in the string is

4.0 N

12.5 N

0.5 N

6.25 N

$T = μ v^{2} = μ \frac{ω ^{2}}{k ^{2}} = 0.04 \frac{( 2 π /0.004 ) ^{2}}{( 2 π /0.50 ) ^{2}} = 6.25 N$

Q. The equation of a wave on a string of linear mass density 0.04kgm−1 is given by y=0.02(m)sin[2π(0.04(s)t​−0.50(m)x​)]. The tension in the string is