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  4. The equation of a wave on a string of linear mass density 0.04 kg m-1 is given by y = 0.02(m)sin[2π ((t/0.04(s))-(x/0.50(m)))]. The tension in the string is

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Q. The equation of a wave on a string of linear mass density $0.04 \,kg\, m^{-1}$ is given by
$y = 0.02\left(m\right)sin\left[2\pi \left(\frac{t}{0.04\left(s\right)}-\frac{x}{0.50\left(m\right)}\right)\right]$.
The tension in the string is

AIEEEAIEEE 2010Waves

Solution:

$T = \mu v^{2} = \mu \frac{\omega^{2}}{k^{2}} = 0.04 \frac{\left(2\pi / 0.004\right)^{2}}{\left(2\pi / 0.50\right)^{2}} = 6.25\,N$