Question

The equation of a projectile is $y=\sqrt{3}x-\frac{g{x}^2}{2}$ The angle of projection is given by

• A. $\tan \theta =\frac{1}{\sqrt{3}}$
• B. $\tan \theta =\sqrt{3}$
• C. $\frac{\pi }{2}$
• D. zero

Answer 1

Answer: (B)

Comparing the given equation with
$y=x\tan \theta -\frac{g{x}^2}{2u^2{\cos }^2\theta }$, we get
$\tan \theta =\sqrt{3}$