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  4. The equation of a projectile is y=√3 x-(g x2/2) The angle of projection is given by

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Q. The equation of a projectile is $y=\sqrt{3} x-\frac{g x^2}{2}$ The angle of projection is given by

Motion in a Plane

Solution:

Comparing the given equation with
$y=x \tan \theta-\frac{g x^2}{2 u^2 \cos ^2 \theta}$, we get
$\tan \theta=\sqrt{3}$