The entropy change in the fusion of one mole of a solid melting at 27° C (Latent heat of fusion, 2930 J mol -1 ) is :

Question

The entropy change in the fusion of one mole of a solid melting at 27° C (Latent heat of fusion, 2930 J mol -1 ) is : (A) 9.77 J K -1 mol -1 (B) 10.73 J K -1 mol -1 (C) 2930 J K -1 mol -1 (D) 108.5 J K -1 mol -1

Tardigrade Admin · Accepted Answer

Δ S =( text Latent heat of fusion / text Melting point )=(Δ H y/ T ) =(2930/300) J K -1 mol -1 =9.77 J K -1 mol -1

Q. The entropy change in the fusion of one mole of a solid melting at $2 7^{\circ} C$ (Latent heat of fusion, $2930 J m o l^{- 1}$ ) is :

$9.77 J K^{- 1} m o l^{- 1}$

$10.73 J K^{- 1} m o l^{- 1}$

$2930 J K^{- 1} m o l^{- 1}$

$108.5 J K^{- 1} m o l^{- 1}$

$Δ S = \frac{Latent heat of fusion}{Melting point} = \frac{Δ H _{y}}{T}$
$= \frac{2930}{300} J K^{- 1} m o l^{- 1}$
$= 9.77 J K^{- 1} m o l^{- 1}$

Q. The entropy change in the fusion of one mole of a solid melting at 27∘C (Latent heat of fusion, 2930Jmol−1 ) is :

9.77JK−1mol−1

10.73JK−1mol−1

2930JK−1mol−1

108.5JK−1mol−1