Question

The entropy change in the fusion of one mole of a solid melting at $27^{\circ} C$ (Latent heat of fusion, $2930 \,J \,mol ^{-1}$ ) is :

• A. $9.77 \,J\, K ^{-1}\, mol ^{-1}$
• B. $10.73 \,J\, K ^{-1} \,mol ^{-1}$
• C. $2930\, J \,K ^{-1}\, mol ^{-1}$
• D. $108.5\, J \,K ^{-1}\, mol ^{-1}$

Answer 1

Answer: (A)

$\Delta S =\frac{\text { Latent heat of fusion }}{\text { Melting point }}=\frac{\Delta H _y}{ T }$
$=\frac{2930}{300} \,J \,K ^{-1} \, mol ^{-1}$
$=9.77 \, J \,K ^{-1} \,mol ^{-1}$