The enthalpy of vaporisation of a liquid is 30 kJ mol -1 and entropy of vaporisation is 75 J mol -1 K -1. The boiling point of the liquid at 1 atm is :

Question

The enthalpy of vaporisation of a liquid is 30 kJ mol -1 and entropy of vaporisation is 75 J mol -1 K -1. The boiling point of the liquid at 1 atm is : (A) 250 K (B) 400 K (C) 450 K (D) 600 K

Tardigrade Admin · Accepted Answer

Δ S=(Δ H text vap. /T)=(30 × 103/75)=400 K

Q. The enthalpy of vaporisation of a liquid is $30 k J m o l^{- 1}$ and entropy of vaporisation is $75 J m o l^{- 1} K^{- 1}$ . The boiling point of the liquid at $1$ atm is :

250 K

400 K

450 K

600 K

$Δ S = \frac{Δ H _{vap.}}{T} = \frac{30 \times 1 0 ^{3}}{75} = 400 K$

Q. The enthalpy of vaporisation of a liquid is 30kJmol−1 and entropy of vaporisation is 75Jmol−1K−1. The boiling point of the liquid at 1 atm is :