1. Tardigrade
  2. Question
  3. Chemistry
  4. The enthalpy of vaporisation of a liquid is 30 kJ mol -1 and entropy of vaporisation is 75 J mol -1 K -1. The boiling point of the liquid at 1 atm is :

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Q. The enthalpy of vaporisation of a liquid is $30\, kJ\, mol ^{-1}$ and entropy of vaporisation is $75 \,J \,mol ^{-1} \,K ^{-1}$. The boiling point of the liquid at $1$ atm is :

Solution:

$\Delta S=\frac{\Delta H_{\text {vap. }}}{T}=\frac{30 \times 10^{3}}{75}=400 \,K$