The enthalpy change for the conversion of (1/2) Cl 2( g ) to Cl -(aq) is (-) kJ mol -1 (Nearest integer) Given: Δ text dis H Cl 2( g ) ominus=240 kJ mol -1, Δ eg H Cl ominus=-350 kJ mol -1, Δ text hyd H θ Cl ( g )-=-380 kJ mol -1

Question

The enthalpy change for the conversion of (1/2) Cl 2( g ) to Cl -(aq) is (-) kJ mol -1 (Nearest integer) Given: Δ text dis H Cl 2( g ) ominus=240 kJ mol -1, Δ eg H Cl ominus=-350 kJ mol -1, Δ text hyd H θ Cl ( g )-=-380 kJ mol -1 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(1/2) Cl 2( g ) arrow Cl ( g ) arrow Cl ( g )- arrow Cl ( aq .)- Δ H °=(1/2) × 240+(-350)+(-380) =-610

Q. The enthalpy change for the conversion of 21​Cl2​(g) to Cl−(aq) is (−)___ kJmol−1 (Nearest integer) Given : Δdis ​HCl2(g)​⊖​=240kJmol−1,Δeg​HCl⊖​=−350kJmol−1, Δhyd ​HθCl(g)−​=−380kJmol−1

21​Cl2(g)​→Cl(g)​→Cl(g)−​→Cl(aq.)−​ ΔH∘=21​×240+(−350)+(−380) =−610

$\frac{1}{2} C l_{2 (g)} \to C l_{(g)} \to C l_{(g)}^{-} \to C l_{(a q .)}^{-}$
$Δ H^{\circ} = \frac{1}{2} \times 240 + (- 350) + (- 380)$
$= - 610$