The enthalpy and entropy change for the reaction: Br2( l )+ Cl 2( g ) arrow 2 BrCl ( g ) are 30 kJ mol -1 and 105 J K -1 mol -1 respectively. The temperature at which the reaction will be in equilibrium is

Question

The enthalpy and entropy change for the reaction: Br2( l )+ Cl 2( g ) arrow 2 BrCl ( g ) are 30 kJ mol -1 and 105 J K -1 mol -1 respectively. The temperature at which the reaction will be in equilibrium is (A) 300 K (B) 285.7 K (C) 273 K (D) 450 K

Tardigrade Admin · Accepted Answer

Br 2(l)+ Cl2( g ) arrow 2 BrCl ( g ) Δ H =30 kJ mol -1, Δ S =105 J K -1 mol -1 Δ S =(Δ H / T ) i.e., 105=(30/ T ) × 1000 ∴ T =(30 × 1000/105)=285.7 K

Q. The enthalpy and entropy change for the reaction :
$B r_{2} (l) + C l_{2} (g) \to 2 B r Cl (g)$
are $30 k J m o l^{- 1}$ and $105 J K^{- 1} m o l^{- 1}$ respectively. The temperature at which the reaction will be in equilibrium is

300 K

285.7 K

273 K

450 K

$B r_{2} (l) + C l_{2} (g) \to 2 B r Cl (g)$
$Δ H = 30 k J m o l^{- 1}, Δ S = 105 J K^{- 1} m o l^{- 1}$
$Δ S = \frac{Δ H}{T}$ i.e., $105 = \frac{30}{T} \times 1000$
$∴ T = \frac{30 \times 1000}{105} = 285.7 K$

Q. The enthalpy and entropy change for the reaction : Br2​(l)+Cl2​(g)→2BrCl(g) are 30kJmol−1 and 105JK−1mol−1 respectively. The temperature at which the reaction will be in equilibrium is