1. Tardigrade
  2. Question
  3. Chemistry
  4. The enthalpy and entropy change for the reaction: Br2( l )+ Cl 2( g ) arrow 2 BrCl ( g ) are 30 kJ mol -1 and 105 J K -1 mol -1 respectively. The temperature at which the reaction will be in equilibrium is

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Q. The enthalpy and entropy change for the reaction :
$Br_2( l )+ Cl _2( g ) \rightarrow 2 BrCl ( g )$
are $30\, kJ\, mol ^{-1}$ and $105\, J \,K ^{-1} \,mol ^{-1}$ respectively. The temperature at which the reaction will be in equilibrium is

NTA AbhyasNTA Abhyas 2022

Solution:

$ Br _2(l)+ Cl_2( g ) \rightarrow 2 BrCl ( g )$
$\Delta H =30\, kJ\, mol { }^{-1}, \Delta S =105 \,J\, K ^{-1} \,mol ^{-1}$
$\Delta S =\frac{\Delta H }{ T }$ i.e., $105=\frac{30}{ T } \times 1000$
$\therefore T =\frac{30 \times 1000}{105}=285.7\, K$