The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV . The possible energy value(s) of the excited state(s) for electron in Bohr orbits of hydrogen is(are):

Question

The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV . The possible energy value(s) of the excited state(s) for electron in Bohr orbits of hydrogen is(are): (A) -6.8 eV (B) -4.2 eV (C) -3.4 eV (D) +6.8 eV

Tardigrade Admin · Accepted Answer

E1 for H=-13.6 eV. En for H=(E1/n2 e) E3=(-13.6/9)=-1.51 eV E4=(-13.6/16)=-0.85 and so on Thus, E2=(-13.6/4)=-3.4 eV

Q. The energy of an electron in the first Bohr orbit of H-atom is $- 13.6 e V$ . The possible energy value(s) of the excited state(s) for electron in Bohr orbits of hydrogen is(are):

-6.8 eV

-4.2 eV

-3.4 eV

+6.8 eV

$E_{1}$ for $H = - 13.6 e V$ .
$E_{n}$ for $H = \frac{E _{1}}{n ^{2} e}$
$E_{3} = \frac{- 13.6}{9} = - 1.51 e V$
$E_{4} = \frac{- 13.6}{16} = - 0.85$ and so on
Thus, $E_{2} = \frac{- 13.6}{4} = - 3.4 e V$

Q. The energy of an electron in the first Bohr orbit of H-atom is −13.6eV . The possible energy value(s) of the excited state(s) for electron in Bohr orbits of hydrogen is(are):