Question

The energy of a photon is given as $3.03\times 10^{-19}J/atom$ . The wavelength of the photon is :-

• A. $6.56nm$
• B. $65.6nm$
• C. $0.656nm$
• D. $656nm$

Answer 1

Answer: (D)

$E=\frac{hc}{\lambda }$
$\lambda =\frac{6.6\times 10^{-34}\times 3\times 10^8}{3.03\times 10^{-19}}$
$\lambda =6.56\times 10^{-7}m$
$\lambda =656nm$