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  4. The energy of a photon is given as 3.03× 10- 19J/atom . The wavelength of the photon is :-

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Q. The energy of a photon is given as $3.03\times 10^{- 19}J/atom$ . The wavelength of the photon is :-

NTA AbhyasNTA Abhyas 2020

Solution:

$E=\frac{hc}{\lambda }$
$\lambda =\frac{6 . 6 \times 10^{- 34} \times 3 \times 10^{8}}{3 . 03 \times 10^{- 19}}$
$\lambda =6.56\times 10^{- 7}m$
$\lambda =656nm$