Question

The energy of a photon corresponding to the visible light maximum wavelength is nearly:

• A. 7 eV
• B. 3.2 eV
• C. 1 eV
• D. 1.6 eV

Answer 1

Answer: (D)

In the visible light ${\lambda }_{\max }=7800\mathring{A}$
$E=\frac{hc}{\lambda }=\frac{12375}{7800}eV=1.6eV$