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Q. The energy of a photon corresponding to the visible light maximum wavelength is nearly:

JIPMERJIPMER 2003Dual Nature of Radiation and Matter

Solution:

In the visible light $\lambda_{\max }=7800\,\mathring{A}$
$E=\frac{h c}{\lambda}=\frac{12375}{7800} eV =1.6 \,eV$