The energy in MeV is released due to transformation of 1 kg mass completely into energy, is (c=3 × 108 m / s )

Question

The energy in MeV is released due to transformation of 1 kg mass completely into energy, is (c=3 × 108 m / s ) (A)  7.625× 10 MeV  (B)  10.5× 1029 MeV (C)  2.8× 10-28 MeV  (D)  5.625× 1029 MeV

Tardigrade Admin · Accepted Answer

According to Einstein's mass energy equivalence E=m c2=1 ×(3 × 108)2=9 × 1016 J =(9 × 1016/1.6 × 10-13) MeV ( text since 1 MeV =1.6 × 10-13 J ) =5.625 × 1029 MeV

Q. The energy in $M e V$ is released due to transformation of $1 k g$ mass completely into energy, is $(c = 3 \times 1 0^{8} m / s)$

$7.625 \times 10 M e V$

$10.5 \times 1 0^{29} M e V$

$2.8 \times 1 0^{- 28} M e V$

$5.625 \times 1 0^{29} M e V$

According to Einstein's mass energy equivalence
$E = m c^{2} = 1 \times (3 \times 1 0^{8})^{2} = 9 \times 1 0^{16} J$
$= \frac{9 \times 1 0 ^{16}}{1.6 \times 1 0 ^{- 13}} M e V$
$(since 1 M e V = 1.6 \times 1 0^{- 13} J)$
$= 5.625 \times 1 0^{29} M e V$

Q. The energy in MeV is released due to transformation of 1kg mass completely into energy, is (c=3×108m/s)

7.625×10MeV

10.5×1029MeV

2.8×10−28MeV

5.625×1029MeV