Question

The energy in $MeV$ is released due to transformation of $1\, kg$ mass completely into energy, is $\left(c=3 \times 10^{8} m / s \right)$

• A. $ 7.625\times 10\,MeV $
• B. $ 10.5\times 10^{29}\,MeV$
• C. $ 2.8\times 10^{-28}\,MeV $
• D. $ 5.625\times 10^{29}\,MeV $

Answer 1

Answer: (D)

According to Einstein's mass energy equivalence
$E=m c^{2}=1 \times\left(3 \times 10^{8}\right)^{2}=9 \times 10^{16} J$
$=\frac{9 \times 10^{16}}{1.6 \times 10^{-13}} MeV$
$\left(\text { since } 1\, MeV =1.6 \times 10^{-13} J \right)$
$=5.625 \times 10^{29}\, MeV$