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Tardigrade
Question
Physics
The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is Ω (Round off to the Nearest Integer)
Q. The energy dissipated by a resistor is
10
m
J
in
1
s
when an electric current of
2
m
A
flows through it. The resistance is ____________
Ω
(Round off to the Nearest Integer)
2276
180
JEE Main
JEE Main 2021
Current Electricity
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Answer:
2500
Solution:
Q
=
i
2
RT
R
=
i
2
t
Q
=
4
×
1
0
−
6
×
1
10
×
1
0
−
3
=
2500
Ω