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Physics
The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is Ω (Round off to the Nearest Integer)
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Q. The energy dissipated by a resistor is $10\,\,mJ$ in $1 \,s$ when an electric current of $2 \,\,mA$ flows through it. The resistance is ____________ $\Omega$ (Round off to the Nearest Integer)
JEE Main
JEE Main 2021
Current Electricity
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Solution:
$Q = i ^{2} \,RT$
$R =\frac{ Q }{ i ^{2} t }=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500 \,\Omega$