The energy density of an electromagnetic wave given by E=(50 N/C) sin(ω t-kx) will be nearly

Question

The energy density of an electromagnetic wave given by E=(50 N/C) sin(ω t-kx) will be nearly (A)  10-8Jm-3  (B)  10-7Jm-3  (C)  10-6Jm-3  (D)  10-5Jm-3

Tardigrade Admin · Accepted Answer

UE=(1/2) ε0 E2=(1/2) × 8.85 × 10-12 ×(50)2 ≈ 108 Jm -3

Q. The energy density of an electromagnetic wave given by $E = (50 N / C) sin (ω t - k x)$ will be nearly

$1 0^{- 8} J m^{- 3}$

$1 0^{- 7} J m^{- 3}$

$1 0^{- 6} J m^{- 3}$

$1 0^{- 5} J m^{- 3}$

$U_{E} = \frac{1}{2} ε_{0}$
$E^{2} = \frac{1}{2} \times 8.85 \times 1 0^{- 12} \times (50)^{2}$
$\approx 1 0^{8} J m^{- 3}$

Q. The energy density of an electromagnetic wave given by E=(50N/C)sin(ωt−kx) will be nearly

10−8Jm−3

10−7Jm−3

10−6Jm−3

10−5Jm−3