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Q. The energy density of an electromagnetic wave given by $ E=(50\,N/C)\sin(\omega t-kx) $ will be nearly

Haryana PMTHaryana PMT 2011

Solution:

$U_{E}=\frac{1}{2} \varepsilon_0$
$E^{2}=\frac{1}{2} \times 8.85 \times 10^{-12} \times(50)^{2}$
$\approx 10^{8} Jm ^{-3}$