The electronic configuration of metal M is 1s2, 2s2, 2p6, 3s1,The formula of its oxide would be

Question

The electronic configuration of metal M is 1s2, 2s2, 2p6, 3s1,The formula of its oxide would be (A) MO (B) M2O (C) M2O3 (D) MO2

Tardigrade Admin · Accepted Answer

Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become M +and will react with O 2- to form M 2 O.

Q. The electronic configuration of metal M is $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1}$ ,The formula of its oxide would be

MO

$M_{2} O$

$M_{2} O_{3}$

$M O_{2}$

Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become $M^{+}$ and will react with $O^{2 -}$ to form $M_{2} O$ .

Q. The electronic configuration of metal M is 1s2,2s2,2p6,3s1,The formula of its oxide would be

MO

M2​O

M2​O3​

MO2​

Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become M+and will react with O2− to form M2​O.

Q. The electronic configuration of metal M is $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1}$ ,The formula of its oxide would be

$M_{2} O$

$M_{2} O_{3}$

$M O_{2}$

Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become $M^{+}$ and will react with $O^{2 -}$ to form $M_{2} O$ .