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Q.
The electronic configuration of metal M is $1s^2, 2s^2, 2p^6, 3s^1$,The formula of its oxide would be
The s-Block Elements
Solution:
Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become $M ^{+}$and will react with $O ^{2-}$ to form $M _{2} O$.