The electronic configuration of four atoms are given in brackets: L(1s2 2s2 2p1); M(1s2 2s2 2p5); Q(1s2 2s2 2p6 3s1); R(1s2 2s2 2p2); The element that would most readily form a diatomic molecule is

Question

The electronic configuration of four atoms are given in brackets: L(1s2 2s2 2p1); M(1s2 2s2 2p5); Q(1s2 2s2 2p6 3s1); R(1s2 2s2 2p2); The element that would most readily form a diatomic molecule is (A) Q (B) M (C) R (D) L

Tardigrade Admin · Accepted Answer

By sharing of 1 electron each, both the atoms of M will get a completed octet.

Q. The electronic configuration of four atoms are given in brackets:
$L (1 s^{2} 2 s^{2} 2 p^{1});$
$M (1 s^{2} 2 s^{2} 2 p^{5});$
$Q (1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1});$
$R (1 s^{2} 2 s^{2} 2 p^{2});$
The element that would most readily form a diatomic molecule is

$Q$

$M$

$R$

$L$

By sharing of $1$ electron each, both the atoms of $M$ will get a completed octet.

Q. The electronic configuration of four atoms are given in brackets: L(1s22s22p1); M(1s22s22p5); Q(1s22s22p63s1); R(1s22s22p2); The element that would most readily form a diatomic molecule is

Q

M

R

L

By sharing of 1 electron each, both the atoms of M will get a completed octet.

Q. The electronic configuration of four atoms are given in brackets:
$L (1 s^{2} 2 s^{2} 2 p^{1});$
$M (1 s^{2} 2 s^{2} 2 p^{5});$
$Q (1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1});$
$R (1 s^{2} 2 s^{2} 2 p^{2});$
The element that would most readily form a diatomic molecule is

$Q$

$M$

$R$

$L$

By sharing of $1$ electron each, both the atoms of $M$ will get a completed octet.