1. Tardigrade
  2. Question
  3. Chemistry
  4. The electronic configuration of four atoms are given in brackets: L(1s2 2s2 2p1); M(1s2 2s2 2p5); Q(1s2 2s2 2p6 3s1); R(1s2 2s2 2p2); The element that would most readily form a diatomic molecule is

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Q. The electronic configuration of four atoms are given in brackets:
$L\left(1s^{2} 2s^{2} 2p^{1}\right); $
$M\left(1s^{2} 2s^{2} 2p^{5}\right); $
$Q\left(1s^{2} 2s^{2} 2p^{6} 3s^{1}\right); $
$R\left(1s^{2} 2s^{2} 2p^{2}\right);$
The element that would most readily form a diatomic molecule is

Chemical Bonding and Molecular Structure

Solution:

By sharing of $1$ electron each, both the atoms of $M$ will get a completed octet.